Volume Calculator

Calculate the volume of 11 common three-dimensional geometric shapes instantly with detailed step-by-step formulas.

Sphere Volume

r
Result💾
Volume = 4/3 πr³
= 4/3 × π × 34³
= 164636.21020892 meters³

Cone Volume

Result💾
Volume = 1/3 πr²h
= 1/3 × π × 3² × 5
= 47.12388980 meters³

Cube Volume

Result💾
Volume = a³
= 4³
= 64.00000000 meters³

Cylinder Volume

Result💾
Volume = πr²h
= π × 3² × 7
= 197.92033717 meters³

Rectangular Tank

Result💾
Volume = l × w × h
= 4 × 3 × 2
= 24.00000000 meters³

Capsule Volume

Result💾
Volume = πr²h + 4/3πr³
= π × 2² × 4 + 4/3 × π × 2³
= 83.77580410 meters³

Spherical Cap

Result💾
Volume = 1/3 πh² (3R - h)
= 1/3 × π × 2² × (3(5) - 2)
= 54.45427252 meters³

Conical Frustum

Result💾
Volume = 1/3 πh (r² + rR + R²)
= 1/3 × π × 5 × (2² + 2×4 + 4²)
= 183.25957146 meters³

Ellipsoid Volume

Result💾
Volume = 4/3 πabc
= 4/3 × π × 3 × 4 × 5
= 251.32741229 meters³

Square Pyramid

Result💾
Volume = 1/3 a²h
= 1/3 × 4² × 6
= 32.00000000 meters³

Tube / Pipe Volume

Result💾
Volume = π × ((d1² - d2²) / 4) × l
= π × ((4² - 3²) / 4) × 8
= 43.98229715 meters³

Understanding Volume and 3D Measurement Principles

Volume measures the total three-dimensional space enclosed inside a closed boundary or object. The international standard (SI) unit for volume is the cubic meter (m³). In practical scenarios, container volume often denotes storage capacity or liquid displacement rather than external dimensions. While regular shapes rely on direct geometric formulas, irregular geometries can be evaluated using calculus or finite element modeling.

1. Sphere

A sphere is a perfectly symmetrical round spatial body where all surface points maintain an equal distance (r) from the exact center point. Unlike flat circles, spherical structures possess volume governed by radial dimensions.

Volume = 4/3 πr³

Example: Filling a spherical water balloon having a radius of 0.15 ft yields a volume of 4/3 × π × 0.15³ = 0.141 ft³.

2. Cone

A cone is a tapered 3D geometric shape that narrows smoothly from a circular base up to a terminal vertex or apex. Only standard right circular cones are addressed here.

Volume = 1/3 πr²h (where r is radius, h is height)

Example: Evaluating a waffle cone with a circular base radius of 1.5 in and height of 5 in gives 1/3 × π × 1.5² × 5 = 11.781 in³.

3. Cube

A cube is a regular hexahedron bound by six congruent square faces meeting at perpendicular 90-degree angles.

Volume = a³ (where a is the edge length)

Example: A cubic container with side edges measuring 2 feet provides a capacity of 2³ = 8 ft³.

4. Cylinder

A cylinder consists of two parallel circular end caps connected by a curved tubular surface of height h.

Volume = πr²h

Example: A cylindrical barrel with radius 3 ft and height 4 ft holds π × 3² × 4 = 113.097 ft³ of material.

5. Rectangular Tank

A rectangular box or cuboid features length, width, and height dimensions that can vary independently across six flat faces.

Volume = length × width × height

Example: Packing a travel case with dimensions 2 ft × 3 ft × 4 ft totals 2 × 3 × 4 = 24 ft³.

6. Capsule

A capsule combines a central cylindrical section capped by two hemispherical ends on both sides.

Volume = πr²h + 4/3πr³

Example: Given radius 1.5 ft and cylinder height 3 ft, the total volume computes to π × 1.5² × 3 + 4/3 × π × 1.5³ = 35.343 ft³.

7. Spherical Cap

A spherical cap represents a rounded segment separated from a full sphere by an intersecting cutting plane.

Volume = 1/3 πh² (3R - h)

Related dimension formulas include finding height or base radius: h = R ± √(R² - r²) and R = (h² + r²) / (2h).

8. Conical Frustum

A conical frustum is the lower portion of a cone remaining after the upper tip is sliced off parallel to its base.

Volume = 1/3 πh (r² + rR + R²)

Example: Using top radius 0.2 in, bottom radius 1.5 in, and height 4 in yields 10.849 in³.

9. Ellipsoid

An ellipsoid is a deformed spherical geometry stretched across three distinct principal perpendicular semi-axes (a, b, c).

Volume = 4/3 πabc

Example: Axis lengths of 1.5 in, 2 in, and 5 in result in 4/3 × π × 1.5 × 2 × 5 = 62.832 in³.

10. Square Pyramid

A square pyramid features a square base foundation and four triangular slopes meeting at a single top vertex.

Volume = 1/3 a²h (where a is base edge, h is height)

Example: A pyramid with base edge 5 ft and height 12 ft gives 1/3 × 5² × 12 = 100 ft³.

11. Tube / Pipe

A hollow tubular pipe volume is calculated by finding the difference between outer and inner cylinder capacities over a specific length (l).

Volume = π × ((d1² - d2²) / 4) × l

Example: Outer diameter 3 ft, inner diameter 2.5 ft, and length 10 ft yields π × ((3² - 2.5²) / 4) × 10 = 21.6 ft³.

Common Volume Units Conversion Reference

Unit Cubic Meters (m³) Milliliters (mL)
Milliliter (cm³)0.0000011
Cubic Inch0.0000163916.39
Pint0.000473473
Quart0.000946946
Liter0.0011,000
Gallon0.0037853,785
Cubic Foot0.02831728,317
Cubic Yard0.764555764,555
Cubic Meter11,000,000
Cubic Kilometer1,000,000,00010¹⁵